Reasoning Inequality Tricks Part - 2 Advanced Level | रीजनिंग ट्रिक पार्ट - 2 एडवांस लेवल

Dear Aspirants,

Today we will solve some questions in the 2nd part of Inequality reasoning. Inequality topic is important in Banking and other exams. In the previous article on this topic, we learned how to solve inequality que. quickly. If you want to know the trick you can read Reasoning Inequality Tricks. In this article, we solve some advanced-level inequality questions and will strengthen this topic.

Que 1. Study the following question carefully and choose the right answer.

Statement: P > Q ≥ Z ≥ V, N < V = S > T

Conclusions: 1. T<Q

                     2. S≥P

$C<$

Options:

1. If only conclusion 1 follows.
2. If only conclusion 2 follows.
3. If either conclusion 1 or conclusion 2 follows.
4. If neither conclusion 1 nor conclusion 2 follows.
5. If both conclusions 1 and 2 follow.

Rule:

Let this symbol of inequality ' < ' be a door. From this open side, we can go forward inside it, & we can not go through its closed side. As shown in the picture below.

Solution:

We have to always check enter point and start from entering, below we have to focus on Q for entering to T.

•  First, check Conclusion 1. T < Q

$\mathrm{Statement:\; P}$$>Q\ge \mathrm{Z\; \ge }V$, $N<V=S>T$

In this, we have to enter from Q to T.  So in the statement, we have to start from Q

Q≥Z ≥V after that continue from V

V = S > T after adding both statements Q ≥ Z ≥ V = S > T {enter}✓              ✓                ✓              ✓Q  ===> ≥  Z ===>  ≥ V ===> ≥ S ===> > T
Q to T enter in all cases but S > T (S is greater than T not equal to greater than ≥) so that's why Q > T conclusion 1 is true.Now check Conclusion 2. S < P

In this, we have to enter from P as we can go without restriction to S. As shown below

$P$$>Q\ge \mathrm{Z\; \ge }\mathrm{V\; =\; S}$

                                 ✓                ✓              ✓           ✓P  ==> > Q ==> ≥ Z  ==> ≥  ==> V = S P > S conclusion 2 is true.so the answer will be Option e: Both conclusions 1 and 2 follow.
Que 2. Study the following question carefully andchoose the right answer.Statement: 2 < 6 ≤ 7 < 8; 9 > 8 = 4 ≤ 5Conclusions: I) 4 ≥ 7

II) 9 > 2

III) 6 < 5

Options:A.  Only conclusion I is trueB.  Only conclusion II is true
C.  Both conclusions I and II are true
D.  Both conclusions II and III are true
E.  Only conclusion III is true

Solution:

Given Statement 2 < 6 ≤ 7 < 8; 9 > 8 = 4 ≤ 5

Conclusion 1: 4 ≥ 7 for checking this we have to go through 4 to 8 and 8 to 7. let's see how we can enter or not because, in conclusion, we have to go through 4 to 7 with sign ≥ 

so statement between (4 to 7) 7 < 8 = 4 so we can see clearly conclusion I is false.

Conclusion: II) 9 > 2 statement between (9 to 2)2 < 6 ≤ 7 < 8 < 9as we can clearly see we can enter from 9 to 2 and sign will be <so 9 > 2 (conclusion II) is true.Conclusion: III) 6 < 5 statement between ( we have to enter from 5 to 6) 6 ≤ 7 < 8 = 4 ≤ 5 so 6 < 5 (conclusion III) is true.Option D.  Both conclusions II and III are true
Que 3. In which of the following expressions does the expression “2 ≥ 1” and “5 ≤ 9” definitely hold true?

A. 5 = 4 ≤ 1 = 2 ≥ 7 ≥ 9

B. 9 = 4 ≤ 5 = 2 > 7 ≥ 1

C. 9 = 4 ≤ 2 = 7 > 5 ≥ 1

D. 5 = 4 ≤ 9 = 2 ≥ 7 ≥ 1

E. None of the above

Solution:

we have to check both expression so

enter through 2 ===> > 1 with ≥ symbol and 9 ===> ≥ 5

First, check Option A in 1 = 2 & 9 can not enter because it is on the closed side of arrow. 

So option A is false.

Option B 2 > 7 ≥ 1 so it is false 2 ≥  1 × for correcting this statement must be 2 ≥ 7 ≥ 1 

also, 9 = 4 ≤ 5 does not give the result of 9 ≥ 5 So option B is false.

From Option C statement 2 = 7 > 5 ≥ 1 and  9 = 4 ≤ 2 = 7 > 5 

also we can clearly see that we can not reach the result.

From Option D statement 2 ≥ 7 ≥ 1 we can reach the result 2 ===> ≥ 1 and from that statement,
          

          5 = 4 ≤ 9 
         

          5 = 4 ≤ <==== 9
          
          9 ===> ≥ 5 is true. So correct Answer is Option D.

Que 4. Statements:
M < D > V ≤ C; K ≥ O = T ≤ P; G ≥ D < O ≥ B

Conclusion:
I) P > V
II) G ≥ M

Sol: Now we solve it quickly by observing. Like, in Conclusion I) we have to enter from P in the statement we can enter from P to T, T to O, O to D then D to V so conclusion 1 is true.

in Conclusion II) we see in statement G  to D and then D to M but in D to M symbol is < but for true conclusion, symbol must be ≤ so this is false.

Answer: I) P > V ✓

              II) G ≥ M ×

Que 5. Statements:
P ≤ Z < E < V; Y ≤ S = B < I; P ≥ I ≤ M

Conclusion:

I) V > B

II) Y < M

Sol: For conclusion I) in given statements we can enter from V to E then E to Z, Z to P, P to I then I to B conclusion I) is true.

and for conclusion II) through statements we have to go through M to I then I to B then B to S and S to Y. Conclusion II) is true.

Answer: I)V > B ✓

              II) Y < M ✓

Que 6. Statements:

X < N ≥ I = A; S ≥ M ≤ P = A

Conclusion:

I) N > M

II) M = N

Sol: In this, we have to go through N to M so N to I, I = A then A = P, P to M but in this between directions are = and ≥ so the final conclusion of this statement is like below

=> N ≥ I = A = P  ≥ M

 

=>   N  ≥ M 

in this case, Answer: Either conclusion I or Conclusion II follows.

So like the above questions, you can solve them in mind and directly tick the correct answer. After Practising more on this topic you can increase the speed of solving. In the next article in part 3 of this topic, we discuss and see the coded inequality problems.

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Your Gyaan INside